Question

Is there anyway to have HAVING and WHERE clauses work in conjecture with each other? ie psuedocode:

CASE
   HAVING count(children) > 3 THEN WHERE nationality = 'Mexican'
   HAVING count(children) = 2 THEN WHERE nationality = 'American'
   HAVING count(children) = 1 THEN WHERE nationality = 'Japanese'
END

Answer 1

You can wrap your query inside of another SELECT

SELECT *
FROM
(
    SELECT count(children) as ChildrenCount, nationality 
    FROM yourTable
    GROUP BY nationality 
) x
WHERE 
    (ChildrenCount > 3 AND nationality = 'Mexican')
    OR
    (ChildrenCount = 2 AND nationality = 'American')
    OR
    (ChildrenCount = 1 AND nationality = 'Japanese')