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Editorial Team
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Editorial Team
Asked: May 30, 20262026-05-30T08:23:57+00:00 2026-05-30T08:23:57+00:00

Is this a reasonable view of Haskell IO? When given a program, the Haskell

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Is this a reasonable view of Haskell IO?

When given a program, the Haskell runtime does the following:

  1. Calls main to get back an “IO computation”
  2. It then executes or “runs” that computation thereby performing all of the side-effects the computation contains.

This two-stage approach allows main to remain a pure function.

An IO computation in this case is like a special version of Haskell that has explicit sequencing – or perhaps there is a better way to describe this?

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  1. Editorial Team
    Editorial Team
    2026-05-30T08:23:58+00:00Added an answer on May 30, 2026 at 8:23 am

    Yeah, that’s a decent semantic model of how the programs are executed. The implementation doesn’t work like that, of course, but you can still use that model to reason about the programs.

    But more generally, what IO does is to allow you to treat imperative programs as pure values. The Monad operations then allow you to compose imperative programs from smaller imperative programs (or to use the usual term in this context, actions) and pure functions. So the purely functional model, while it cannot execute imperative programs, can still describe them as expressions of type IO a, and the compiler can translate these descriptions into imperative code.

    Or you could say this:

    • The compiler (not the runtime) evaluates main.
    • The result of that evaluation is an imperative program.
    • This program is saved to the target executable.
    • You then execute the target program.

    I.e., the “evaluate main” part of your model is pushed to the compiler, and is not in the runtime as you first describe it.

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