Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 8638761
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: June 12, 20262026-06-12T10:49:09+00:00 2026-06-12T10:49:09+00:00

Is this possible and if so how? (I haven’t been able to find a

  • 0

Is this possible and if so how? (I haven’t been able to find a way for it to work)

var foo = function() 
{ 
    console.log("Original Function");
    this = function() 
    {
        console.log("New Function");
    }
};
console.log("Calling foo()");
foo();

Desired output:

Original Function

Calling foo()

New Function

To answer the questions in advance, yes I know there are other ways to do this. I’m just curious if I could do something like var bar = new foo(); and have foo() assign some time dependent properties to itself without an extra function.

EDIT: Response to Charmanders question, and a slightly less simplified, more practical application

var node = function(parent)
{
    this = function()
    {
        for (i in this)
        {
            // perform actions (which will occasionally include calling i()
        }
    }
    if (parent !== null)
    {
        this.parent = parent;
        // code to determine children
        this.somechild = new node(this);
        this.someotherchild = new node(this);
    }
};
var ancestor = new node(new node(null));
  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-06-12T10:49:11+00:00Added an answer on June 12, 2026 at 10:49 am

    Assigning a new value to this will not work, but you can simply return a function:

    var foo = function() { 
        console.log("Original Function");
        return function() {
            console.log("New Function");
        };
    };
    
    console.log("Calling foo()");
    var f = foo(); /* or even: f = new foo(); */
    f();
    
    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

Is it possible to do this? I haven't been able to find anything in
I haven't been able to find anything online regarding this. There's RegexOptions, but it
I haven't been able to find an answer to this question. I used Nu
I have googled the heck out of this, but haven't been able to find
I've been looking for an efficient way to do this but haven't been able
Might be a silly question, but I haven't been able to find an answer
I haven't been able to come up with a clear answer on this, so
I'm learning the Flex command-line debugger, and I haven't been able to find information
I believe this is possible but I haven't done it before. I need to
Is this possible? A group of us have been trying to prepare for a

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.