Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 6710683
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 26, 20262026-05-26T08:03:02+00:00 2026-05-26T08:03:02+00:00

Is this the correct way of accessing all pixels in cv::Mat : for( row

  • 0

Is this the correct way of accessing all pixels in cv::Mat:

for( row = 0; row < mat.rows; ++row) 
    {
            for ( col = 0; col < mat.cols; ++col) 
            {



            }
    }

Or is there a formula method similar to this formula for an IplImage *:

temp_ptr = &((uchar*)(img->imageData + (img->widthStep*pt.x)))[pt.y*3];
  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-26T08:03:02+00:00Added an answer on May 26, 2026 at 8:03 am

    In the best case, where all the pixels are stored contiguously you should be able to do:

    uchar* pixel = mat.data;
    for(int i = 0; i < mat.rows * mat.cols; ++i) 
    {
        // access pixel[0],pixel[1],pixel[2] here
        pixel += 3; // move to next pixel
    }
    

    To be a bit more generic, but still fast, have a look at the sample code mentioned with Mat::isContinuous(). The general formula for calculating the address of an element can be seen here (Reproduced below).

    Address calculation

    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

Is this the correct way of accessing session variables in classes. I am not
Is this the correct way to do it? <a id=load href=# class=btn load onclick=request(this);
Is this the correct way to obtain the most negative double in Java? double
Is this the correct way to pass two ids in jQuery? I am having
Is this the correct way to update a ProgressBar when playing Media? I figured
This is a simple question: Is this a correct way to get an integer
Would this be the correct way of declaring that an XML element Cluster contains
I'm not sure if this is the correct way to synchronize my ArrayList .
I'm still not sure this is the correct way to go about this, maybe
How would you correct way to handle an exception in this situation? Initially I

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.