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Editorial Team
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Asked: 2026-05-21T14:06:04+00:00

Is this well defined behavior? const char* p = (std::string(Hello) + std::string(World)).c_str(); std::cout <<

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Is this well defined behavior?

const char* p = (std::string("Hello") + std::string("World")).c_str();
std::cout << p;

I am not sure. Reasons?

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1 Answer

  1. Editorial Team

    No, this is undefined behavior. Both std::string temporaries and the temporary returned by operator+ only live until the end of the initialization of your const char* (end of full expression). Then they are destroyed and p points to uncertain memory.

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