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Home/ Questions/Q 8168511
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Editorial Team
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Editorial Team
Asked: June 6, 20262026-06-06T20:33:05+00:00 2026-06-06T20:33:05+00:00

Isn’t there another way of using global variables in a Java stlye manner in

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Isn’t there another way of using global variables in a Java stlye manner in PHP without the use of the global keyword?

The below example is something very common and simple. I would do it with the define keyword, but as you can see, the varibales are dependent from each other, and I believe you can’t achieve that with define.

In the below example I am getting an error, of course.

Really looking forward a solution for this. It just seems to me that having to write a global definition for which funciton I want to use a global variable seems such an ineffective solution that should be a better one.

$BASE_URL = "mysite.com";
$PRODUCTS_URL = $BASE_URL . "/products";
$ABOUT_URL = $BASE_URL . "/about";

function foo() {
    echo $BASE_URL;
}
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  1. Editorial Team
    Editorial Team
    2026-06-06T20:33:08+00:00Added an answer on June 6, 2026 at 8:33 pm

    I would do it with the define keyword, but as you can see, the varibales are dependent from each other, and I believe you can’t achieve that with define.

    Not quite true, this will work just fine – and it’s the way I would probably approach this:

    define('BASE_URL', "mysite.com");
    define('PRODUCTS_URL', BASE_URL . "/products");
    define('ABOUT_URL', BASE_URL . "/about");
    

    Just be careful about eating up constant namespace, you might want to write a function instead, maybe something like this (could use tweaking, just an example):

    function get_url($item = NULL, $include_base = TRUE)
    {
        $urls = array(
            'base'  =>  'mysite.com',
            'products'  =>  '/products',
            'about' =>  '/about',
        );
        $output = $include_base ? $urls['base'] : '';
        if (isset($urls[$item])) $output .= $urls[$item];
        return $output;
    }
    

    Then call it like echo get_url('products');. As long as this is defined when foo() is called, it will work. I would always strive to avoid global or $GLOBALS.

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