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Home/ Questions/Q 8860177
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Editorial Team
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Editorial Team
Asked: June 14, 20262026-06-14T15:13:05+00:00 2026-06-14T15:13:05+00:00

It appears that std::remove_const isn’t able to remove the const-ness of const char* .

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It appears that std::remove_const isn’t able to remove the const-ness of const char*. Consider the following code:

#include <iostream>
#include <type_traits>
#include <typeinfo>

template< typename T >
struct S
{
    static void foo( ) {
        std::cout << typeid(T).name() << std::endl;
        std::cout << typeid( std::remove_const<T>::type ).name() << std::endl;
    }
};


int main( )
{
    S<char const*>::foo();
}

Output of this program (on Visual Studio 2010):

char const *
char const *

And in gcc we have the readable output (code here):

PKc
PKc

I would hope to get char * on the second line of Microsoft compiler, and whatever (but different than 1st line) on gcc. What am I doing wrong? How do I turn char const* to char*?

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  1. Editorial Team
    Editorial Team
    2026-06-14T15:13:05+00:00Added an answer on June 14, 2026 at 3:13 pm

    If you want to remove all const qualifiers you need a solution that recursively removes const from all levels:

    template<typename T> struct remove_all_const : std::remove_const<T> {};
    
    template<typename T> struct remove_all_const<T*> {
        typedef typename remove_all_const<T>::type *type;
    };
    
    template<typename T> struct remove_all_const<T * const> {
        typedef typename remove_all_const<T>::type *type;
    };
    
    int main() {
        std::cout << typeid(remove_all_const<int const * * const>::type).name() << '\n';
    }
    
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