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Editorial Team
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Asked: 2026-05-23T00:48:51+00:00

it has error because $_POST[‘sub1’] can’t be accessed is there any approach or solution

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it has error because $_POST[‘sub1’] can’t be accessed
is there any approach or solution to echo the value of $_POST[‘sub1’]? or impossible? no way? even with another arrays?
i had question about my code nobody solved it! then I decide to tell it in simple way.

<html>
<form method="post">
<input type='submit' name='sub1' value='sub1'>
<?php
if(array_key_exists('sub1',$_POST))
{
echo"<input type='submit' name='sub2' value='sub2'>";
}
if(array_key_exists('sub2',$_POST))
{
echo $_POST['sub1'];
}
?>
</form>
</html>
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1 Answer

  1. Editorial Team

    I think I know what is wrong here.

    When you submit the form the second time (for sub2) you are no longer posting the value of sub1 along with it, just sub2.

    This should fix it:

    <html>
<form method="post">
<input type='submit' name='sub1' value='sub1'>
<?php
if(array_key_exists('sub1',$_POST))
{
echo"<input type='hidden' name='sub1' value='" . htmlentities($_POST['sub1']) . "'>";
echo"<input type='submit' name='sub2' value='sub2'>";
}
if(array_key_exists('sub2',$_POST))
{
echo $_POST['sub1'];
}
?>
</form>
</html>
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