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Editorial Team
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Asked: 2026-05-27T10:43:59+00:00

It is a bit complicated to explain into the main caption, but the situation

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It is a bit complicated to explain into the main caption, but the situation is as follow :
– I have 2 tables :
Users, Preferences.

defined as follow

Users :

ID | NAME | FK_NODE_PREFERENCES

Preferences :

ID | FK_USERS | PREFERENCE_DESCRIPTION

the idea is to have alot of preferences for each user…

the results shall look as follow :

USER | ALL_PREFERENCES
  • I need to search by a part of the preference string and i need to have only 1 row into the result select query, which having all the preferences related ot the user as a text into a single record ?
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1 Answer

  1. Editorial Team

    I’m not familiar with Firebird, but it seems to have a LIST() function which should be an equivalent to the GROUP_CONCAT() function in MySQL. (see documentation of LIST())

    So, basically the query should look something like this:

    SELECT Users.name, LIST(Preferences.preference_description, ' ') AS ALL_PREFERENCES FROM Users JOIN NodePreferences ON Users.fk_node_preferences = Preferences.id WHERE Preferences.preference_description LIKE '%abc%' GROUP BY Users.name

    So, I’m not sure if this actually works, but the direction should be the right one.

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