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Home/ Questions/Q 6932689
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T11:44:14+00:00 2026-05-27T11:44:14+00:00

It is my first attempt to use pyparsing and I’d like to ask how

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It is my first attempt to use pyparsing and I’d like to ask
how to filter this sample line:

survey = '''GPS,PN1,LA52.125133215643,LN21.031048525561,EL116.898812'''

to get output like: 1,52.125133215643,21.031048525561,116.898812

In general I have problem with understanding pyparsing logic so any help with this
example will be appreciated. Thanks

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-27T11:44:15+00:00Added an answer on May 27, 2026 at 11:44 am

    You could start with something like this:

    from pyparsing import *
    
    survey = '''GPS,PN1,LA52.125133215643,LN21.031048525561,EL116.898812'''
    
    number = Word(nums+'.').setParseAction(lambda t: float(t[0]))
    separator = Suppress(',')
    latitude = Suppress('LA') + number
    longitude = Suppress('LN') + number
    elevation = Suppress('EL') + number
    
    line = (Suppress('GPS,PN1,')
            + latitude
            + separator
            + longitude
            + separator
            + elevation)
    
    print line.parseString(survey)
    

    The output of the script is:

    [52.125133215643, 21.031048525561, 116.898812]
    

    Edit: You might also want to consider lepl, which is a similar library that’s pretty nicely documented. The equivalent script to the one above is:

    from lepl import *
    
    survey = '''GPS,PN1,LA52.125133215643,LN21.031048525561,EL116.898812'''
    
    number = Real() >> float
    
    with Separator(~Literal(',')):
        latitude = ~Literal('LA') + number
        longitude = ~Literal('LN') + number
        elevation = ~Literal('EL') + number
    
        line = (~Literal('GPS')
                 & ~Literal('PN1')
                 & latitude
                 & longitude
                 & elevation)
    
    print line.parse(survey)
    
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