Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 6869471
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 27, 20262026-05-27T03:33:42+00:00 2026-05-27T03:33:42+00:00

It is my understanding that setting an ivar now retains the object being assigned

  • 0

It is my understanding that setting an ivar now retains the object being assigned to it, since setting variables defaults to the strong qualifier. Because ivars are in the scope of the object they are declared in and strong retains objects within the scope of the variable, this means the ivars value would never be released while the object containing the ivar is still alive.

Is this correct?

If so, am I right in thinking that there is, in terms of memory management, no difference between a retaining (strong) property and a simple ivar anymore?

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-27T03:33:42+00:00Added an answer on May 27, 2026 at 3:33 am

    If a variable:

    1. Is declared in a class using ARC.
    2. Is used solely for class implementation (not exposed as part of the class interface).
    3. Does not require any KVO.
    4. Does not require any custom getter/setter.

    Then it is appropriate to declare it as an ivar without a corresponding @property/@synthesize, and to refer to it directly within the implementation. It is inline with Encapsulation to declare this ivar in the class implementation file.

    // MyClass.h
    @interface MyClass : ParentClass
    @end
    
    // MyClass.m
    @implementation MyClass {
        NSString *myString;
    }
    
    - (void)myMethod {
        myString = @"I'm setting my ivar directly";
    }
    @end
    
    • This ivar will be treated as __strong by the ARC compiler.
    • It will be initialized to nil if it is an object, or 0 if it is a primitive.
    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

It's my understanding that all .NET object instances begin with an 8 byte 'object
Understanding that I should probably just dig into the source to come up with
It is my understanding that two unequal objects can have the same hashcode. How
It's my understanding that in Spring, all objects are treated by default as singletons.
It's my understanding that all three of these lines below should return an ARRAY
It is my understanding that a texture atlas is basically a single texture that
So it's my understanding that on a ReaderWriterLock (or ReaderWriterLockSlim more specifically), both the
It is my understanding that although Mercurial has support from branches, the community generally
It's my understanding that, in terms of selector speed, that #ID selectors are fastest,
It is my understanding that one can handle events through Swing by adding a

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.