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Home/ Questions/Q 6204675
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Editorial Team
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Editorial Team
Asked: May 24, 20262026-05-24T05:08:19+00:00 2026-05-24T05:08:19+00:00

It is well known, that generic types don’t survive the compiling process. They are

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It is well known, that generic types don’t survive the compiling process. They are replaced by class casts.

But nevertheless, the type information is present in the class file and can be seen using reflection:

public class Demo
{
    private List<String> list;

    public Demo() throws SecurityException, NoSuchFieldException
    {
        System.out.println(((Class<?>)((ParameterizedType) getClass().getDeclaredField("list").getGenericType()).getActualTypeArguments()[0]).getName());
    }

    public static void main(String[] args) throws SecurityException, NoSuchFieldException
    {
        new Demo();
    }
}

When executed, this will print java.lang.String.

Can a JIT use this for some kind of optimization? Or is that information from the point of view of the JIT useless?

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  1. Editorial Team
    Editorial Team
    2026-05-24T05:08:20+00:00Added an answer on May 24, 2026 at 5:08 am

    It could, but as far as I know it doesn’t. To work around this, Scala added support somewhat recently to compile-time type specialization of generic code which generates specialized versions of the class – without any casts – and places them to the rest of the codebase transparently so that the code still works as expected. In these cases, compiled Scala code can actually be noticeably faster than Java since Java with Generics will always use casts.

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