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Home/ Questions/Q 8672373
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Editorial Team
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Editorial Team
Asked: June 12, 20262026-06-12T19:11:15+00:00 2026-06-12T19:11:15+00:00

It looks like the original functionality of Array.lastIndexOf was what I’m looking for, but

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It looks like the original functionality of Array.lastIndexOf was what I’m looking for, but it was changed. Any idea how to replicate the old functionality?

http://blog.sugarjs.com/post/8452749291/v0-9-2-indexof-lastindexof-fixed

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  1. Editorial Team
    Editorial Team
    2026-06-12T19:11:16+00:00Added an answer on June 12, 2026 at 7:11 pm

    After looking at the sugar.js docs, it appears that Array#findIndex does the reverse of what I’m trying to do, so here’s my solution which uses that:

    Array.prototype.findLastIndex = function(f, startIndex, loop) {
        var reverseIndex = this.clone().reverse().findIndex(f, startIndex, loop);
        if (reverseIndex < 0) {
            return reverseIndex;
        }
        return this.length - reverseIndex - 1;
    };
    
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