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Home/ Questions/Q 843841
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Editorial Team
  • 0
Editorial Team
Asked: May 15, 20262026-05-15T06:11:36+00:00 2026-05-15T06:11:36+00:00

it not work with png created a thumb png but haven’t data , like

  • 0

it not work with png
created a thumb png but haven’t data , like null data 😀
with jpg , jpeg still working without error
why ?

function thumbnail($pathtoFile,$thumWidth,$pathtoThumb) {

    //infor of image
    $infor = pathinfo($pathtoFile);

    // Setting the resize parameters 
    list($width, $height) = getimagesize($pathtoFile); 

    $modwidth = $thumWidth; 
    $modheight = floor( $height * ( $modwidth / $width )); 


    // Resizing the Image 
    $thumb = imagecreatetruecolor($modwidth, $modheight);

    switch(strtolower($infor['extension'])) {
        case 'jpeg':
        case 'jpg':
            $image = imagecreatefromjpeg($pathtoFile); 
            break;

        case 'gif':
            $image = imagecreatefromgif($pathtoFile); 
            break;

        case 'png':
            $image = imagecreatefrompng($pathtoFile); 
            break;
    }

    imagecopyresampled($thumb, $image, 0, 0, 0, 0, $modwidth,
            $modheight, $width, $height);

    switch(strtolower($infor['extension'])) {
        case 'jpeg':
        case 'jpg':
            imagejpeg($thumb,$pathtoThumb, 70); 
            break;
        case 'gif':
            imagegif($thumb,$pathtoThumb, 70); 
            break;
        case 'png':

            imagepng($thumb,$pathtoThumb, 70); 
            break;
    }

    //destroy tmp
    imagedestroy($thumb);
}
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-15T06:11:37+00:00Added an answer on May 15, 2026 at 6:11 am

    It isn’t working because imagepng() third argument must be between 0 and 9. It indicates the compression level of the png image (0 being no compression). 70 is not a valid value.

    imagepng($thumb, $pathtoThumb, 9);
    

    Also, imagegif() only accepts two arguments. Technically, your call should be:

    imagegif($thumb, $pathtoThumb);
    
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