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Home/ Questions/Q 6181673
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Editorial Team
  • 0
Editorial Team
Asked: May 24, 20262026-05-24T01:04:01+00:00 2026-05-24T01:04:01+00:00

It says the error is in the while loop. <?php $my_connection = mysql_connect(‘localhost’,’root’,”); if(!$my_connection){

  • 0

It says the error is in the while loop.

    <?php

    $my_connection = mysql_connect('localhost','root','');

    if(!$my_connection){
            die('Could not connect: ' . mysql_error());
    }

    echo 'Connected successfully' . '<br><br>';

    $my_database = mysql_select_db('jihoon');

    if(!$my_database){
        die('Could not find database: ' . mysql_error());
    }

    $query='SELECT * FROM comments";

    $result=mysql_query($query);

    $my_rows;

    while($row = mysql_fetch_array($result, MYSQL_ASSOC)){
        $my_rows = $my_rows . "id : {$row['id']}";
    }

    mysql_close($my_connection);

    ?>
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-24T01:04:02+00:00Added an answer on May 24, 2026 at 1:04 am

    If you take a look at the syntax-coloring of your question, here on StackOverflow, you’ll notice that it starts getting broken at this line :

    $query='SELECT * FROM comments";
    

    You must use the same kind of quote at the beginning and end of your string.

    So, you should use either :

    $query='SELECT * FROM comments';
    

    or :

    $query="SELECT * FROM comments";
    

    But not a bit of both 😉

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