Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 6672859
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 26, 20262026-05-26T03:33:29+00:00 2026-05-26T03:33:29+00:00

It seems silly to write the following: L = [] if x in L:

  • 0

It seems silly to write the following:

L = []

if x in L:
  L[x] = something
else:
  L[x] = something_else

Doesn’t this perform the look-up for x twice? I tried using index(), but this gives an error when the value is not found.

Ideally I would like to say like:

if x is in L, save that index and:
  ...

I can appreciate that this might be a beginner python idiom, but it seems rather un-search-able. Thanks.

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-26T03:33:30+00:00Added an answer on May 26, 2026 at 3:33 am

    Another option is try/except:

    d = {}
    try:
        d[x] = something_else
    except KeyError:
        d[x] = something
    

    Same result as your code.

    Edit: Okay, fast moving target. Same idiom for a list, different exception (IndexError).

    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

I'm new to PHP so I apologize if this seems silly. I've searched around
I am new to jquery so please excuse me if this question seems silly...
Ok this seems so silly but I'm having some trouble getting this to work.
Sorry if this seems like a silly question - I am an amateur when
Ok, so this seems like a really silly problem but I can't get my
I'm using Symfony 1.4 with Doctrine. Sorry if this is a silly question but
This seems silly, but I don't understand how Django Templates access nested data in
I often find I want to write code something like this in C#, but
This almost seems silly but what is the most reliable pattern to follow when
May be this seems silly question for you guys.. Its about CSS Sprites. I

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.