Home/ Questions/Q 6015079
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Asked: 2026-05-23T02:47:03+00:00

it seems this only work on even numbers: 8|0 + 1 // 9 3|0

  • 0

it seems this only work on “even” numbers:

"8"|0 + 1   // 9
"3"|0 + 1   // 3
("3"|0) + 1 // 4

but "3"|0 translates to the Integer 3.

so what’s going on here?
why does the second example acts like this in JS?

Share

Leave an answer

You must login to add an answer.

Need An Account,

1 Answer

  1. Editorial Team

    The precedence of + is higher than |.

    So it’s parsing like this:

    "8" | (0 + 1) = "8" | 1 = 9
"3" | (0 + 1) = "3" | 1 = 3
    • 0