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Asked: 2026-06-15T22:06:54+00:00

It will be easier to explain my problem by explaining the code at first.

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It will be easier to explain my problem by explaining the code at first.

def initialize_function(num,instruction,emplacement1,emplacement2,current_pipeline):
    function_mapping={
    "LOAD" : LOAD(num,emplacement1,emplacement2,current_pipeline),
    "STORE" : STORE(num,emplacement1,emplacement2,current_pipeline),
    "MOVE" : MOVE_IADD(num,emplacement1,emplacement2,current_pipeline),
    "IADD" : MOVE_IADD(num,emplacement1,emplacement2,current_pipeline),
    "FADD" : FADD(num,emplacement1,emplacement2,current_pipeline)
    }
    current_pipeline=function_mapping[instruction] 
    return(current_pipeline)

The initialize_function function has an argument instruction. instruction is a string equivalent to one of the keys of the function_mapping dictionnary.
So when I do current_pipeline=function_mapping[instruction] it is supposed to execute only the value of the instruction. But it doesn’t. Actually the function_mapping dictionnary is initialized before it looks for the key instruction so it executes one after the other all the functions LOAD,STORE,MOVE,IADD,FADD.

What can I do ?

Thank you in advance 🙂

MFF

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1 Answer

  1. Editorial Team

    Since the arguments to all of your functions are the same this should work:

    def initialize_function(num,instruction,emplacement1,emplacement2,current_pipeline):
    function_mapping={
    "LOAD" : LOAD,
    "STORE" : STORE,
    "MOVE" : MOVE_IADD,
    "IADD" : MOVE_IADD,
    "FADD" : FADD
    }
    current_pipeline=function_mapping[instruction](num,emplacement1,emplacement2,current_pipeline)
    return(current_pipeline)

    Explanation: Your dictionary values will evaluated at runtime since you are actually calling the functions. You want to pass a reference to them instead and since functions are first class objects in python, you can do just that.

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