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Home/ Questions/Q 4615890
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Editorial Team
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Editorial Team
Asked: May 22, 20262026-05-22T01:54:16+00:00 2026-05-22T01:54:16+00:00

$(.IT_Badge).each(function(){ var badges = $(.IT_Badge).val().trim().split(,); for (c = 0; badges.length > c; c++) {

  • 0
$(".IT_Badge").each(function(){
    var badges = $(".IT_Badge").val().trim().split(",");
    for (c = 0; badges.length > c; c++) {
        currentBadge = badges[c];
        currentBadge.replaceWith($("<img/>").attr("src", 'IT_Badges/' + badges[c] + '.png'));
    }
});

I have multiple spans with keywords in them. I need to replace the keywords with images who’s src is the keyword. However, i’m worried that the images placed in the span will be placed in all spans called IT_Badge, hence the for loop and the each. I want the replacement to be on a span by span basis.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-22T01:54:17+00:00Added an answer on May 22, 2026 at 1:54 am

    You are not setting iconInst to an array every time in the first itteration. It appears that iconInst is not an array by the second itteration. Is this a typo? I think you intended to do

    var iconInst = [];
    $(".IT_Badge").each(function(i, el){
        iconInst.push($(this).addClass('Inst' + i));
    });
    
    iconInst.each(function(){
        var badges = $(this).val().trim().split(",");
        for (c = 0; words.length > c; c++) {
            $(this).contents().replaceWith($("<img/>").attr("src", 'Icon/' + badges[c] + '.png'));
        }
    });
    

    If that is the case, please update the question and we’ll continue from there, if not I am not very clear as to what the issue you are trying to deal with is.

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