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Editorial Team
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Editorial Team
Asked: May 16, 20262026-05-16T23:08:35+00:00 2026-05-16T23:08:35+00:00

iterate :: (a -> a) -> a -> [a] (As you probably know) iterate

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iterate :: (a -> a) -> a -> [a]

(As you probably know) iterate is a function that takes a function and starting value. Then it applies the function to the starting value, then it applies the same function to the last result, and so on.

Prelude> take 5 $ iterate (^2) 2
[2,4,16,256,65536]
Prelude> 

The result is an infinite list. (that’s why I use take).
My question how would you implement your own iterate' function in Haskell, using only the basics ((:) (++) lambdas, pattern mataching, guards, etc.) ?

(Haskell beginner here)

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  1. Editorial Team
    Editorial Team
    2026-05-16T23:08:35+00:00Added an answer on May 16, 2026 at 11:08 pm

    Well, iterate constructs an infinite list of values a incremented by f. So I would start by writing a function that prepended some value a to the list constructed by recursively calling iterate with f a:

    iterate :: (a -> a) -> a -> [a]
    iterate f a = a : iterate f (f a)
    

    Thanks to lazy evaluation, only that portion of the constructed list necessary to compute the value of my function will be evaluated.

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