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Home/ Questions/Q 6660731
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T02:11:30+00:00 2026-05-26T02:11:30+00:00

its been awhile since i used java the last time and am trying to

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its been awhile since i used java the last time and am trying to brush up on couple of things.

import java.util.*;

public class bitStrings {
    public static void main(String [] args){

        Scanner inputBitString = new Scanner(System.in);        

        //input.
        String binArray;

        ArrayList<String> myArr = new ArrayList<String>();

        while(inputBitString.hasNext()){

            binArray=inputBitString.next();         
            myArr.add(binArray);
            System.out.println(myArr);      

            for(int i=0;i<myArr.size();i++){
                if(myArr(i)=="1") myArr(i)=="10";
                else myArr(i)=="01"
            }
        }

    }

}

So I want to store the input in an array from the user’s keyboard input. so if the user types “1010”, the for loop will go through the array and replaces the “1” with “10” and “0” with “01”.
so the resulting output will be “10011001”

Thanks

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-26T02:11:31+00:00Added an answer on May 26, 2026 at 2:11 am

    You can use this:

    ArrayList<String> myArr = new ArrayList<String>();
    ArrayList<String> myArrDub = new ArrayList<String>();
    BufferedReader bf = new BufferedReader(new InputStreamReader(System.in));
    String str = bf.readLine();
    
    for (int i=0; i<str.length(); i++) {
        String tempStr = new String();
        tempStr += str.charAt(i);
        myArr.add(tempStr);
    }
    
    System.out.println(myArr);
    
    for(int i=0;i<myArr.size();i++){
        if(myArr.get(i).equals("1"))
        myArrDub.add("10");
    else
        myArrDub.add("01");
    }
    
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