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Home/ Questions/Q 7876857
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Editorial Team
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Editorial Team
Asked: June 3, 20262026-06-03T03:14:02+00:00 2026-06-03T03:14:02+00:00

It’s my understanding that GHC gives each thread a stack. Why is this necessary?

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It’s my understanding that GHC gives each thread a stack. Why is this necessary? Doesn’t GHC compile to CPS? Isn’t a thread expressed concisely as a closure?

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  1. Editorial Team
    Editorial Team
    2026-06-03T03:14:03+00:00Added an answer on June 3, 2026 at 3:14 am

    There are several aspects to your question.

    The key reference for the design decisions in the GHC runtime is the paper ”Runtime Support for Multicore Haskell”.

    Recall that

    The GHC runtime system supports millions of lightweight threads
    by multiplexing them onto a handful of operating system threads,
    roughly one for each physical CPU.

    And:

    Each Haskell thread runs on a finite-sized stack, which is allocated in
    the heap. The state of a thread, together with its stack, is kept in a
    heap-allocated thread state object (TSO). The size of a TSO is around
    15 words plus the stack, and constitutes the whole state of a Haskell
    thread. A stack may grow by copying the TSO into a larger area, and
    may subsequently shrink again

    GHC does not compile via CPS. Each thread make recursive calls, and they must allocate to the stack. By representing the stack as a heap-allocated object, things are made simpler.

    A thread is more than a closure.

    As a thread executes, it starts allocating to the heap and stack. Thus:

    The stack of a thread, and hence its TSO, is mutable. When a
    thread executes, the stack will accumulate pointers to new objects,
    and so if the TSO resides in an old generation it must be added to
    the remembered set [of the GC].

    Garbage collecting objects pointed at by stacks can be optimized to ensure GC takes place on the same physical thread as the thread.

    Furthermore, when the garbage collector runs,
    it is highly desirable that the TSOs that have been executed on a
    given CPU are traversed by the garbage collector on the same CPU,
    because the TSO and data it refers to are likely to be in the local
    cache of that CPU.

    So, GHC has a stack for each thread because the compilation mandates that threads have access to a stack and a heap. By giving each thread its own stack, threads can execute in parallel more efficiently. Threads are more than “just a closure”, since they have a mutable stack.

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