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Home/ Questions/Q 7431129
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Editorial Team
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Editorial Team
Asked: May 29, 20262026-05-29T09:14:52+00:00 2026-05-29T09:14:52+00:00

it’s should be something really simple if its possible. anyway of doing so? can’t

  • 0

it’s should be something really simple if its possible. anyway of doing so? can’t seem to find it online.

i have a set of checkboxes and textboxes beside it. i only want the textboxes to appear if i check it. my ids are dynamic using php so i cant use javascript out of the loop.

the code below is to test if it works to hide. i am able to hide on click but iam hoping to do the other way round.

while($row = mysql_fetch_array($result)){
                echo "<tr>";
                echo "<td><input name='CBox $TBCounter' type=\"checkbox\" value=\"{$row['type']}\" onclick=\"document.getElementById('TBox $TBCounter').style.visibility='hidden';\"/></td>";
                echo "<td>" . $row['type'] . "</td>
                <td><input type=\"text\" name=\"mytext\" id=\"TBox $TBCounter\"></td><br />
                            </tr>";
                $TBCounter++;
            }
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  1. Editorial Team
    Editorial Team
    2026-05-29T09:14:52+00:00Added an answer on May 29, 2026 at 9:14 am

    You can use Javascript’s window.onload to make something run every time the page loads.


    Before your loop…

    $elementsToHide = array();
    

    During your loop, put this

    $elementsToHide[] = $TBCounter;
    

    Then make your script (after the loop) look like this

    <script type="text/javascript">
        window.onload = function ()
        {
            <?php foreach ($elementsToHide AS $TBCounter): ?>
            document.getElementById('TBox <?php echo $TBCounter ?>').style.visibility = 'hidden';
            <?php endforeach ?>
        }
    </script>
    
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