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Home/ Questions/Q 6931325
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T11:33:44+00:00 2026-05-27T11:33:44+00:00

I’ve a hard time figuring out how to make the parent class functions visible

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I’ve a hard time figuring out how to make the parent class functions visible in C#.

Assume I’ve a template class, which defines a function foo()

template <int Dim, typename Type>
public ref class FixedNP
{
public:
  float foo() {return 1;};
};

Then I’ve a class which inherits from the FixedNP template:

public ref class Vector3fP : public FixedNP<3, float>
{
}

When I try to call the foo() function from the C#, eg.

Vector3fP bar = new Vector3fP();
bar.foo();

it says the function Vector3fP doesn’t contain a definition for foo.

When I move the definition of foo() to the Vector3fP class, it works fine. However this is not viable in real code, because the FixedNP template contains quite a lot of functions which should be inherited from approximately 4 different classes.

After some search on the Internet I found that adding the

using FixedNP<3, float>::foo;

to the Vector3fP fixed a similar problem for someone. However in my case it just results in another error, this time when compiling the C++/CLI code:

error C3182: ‘Vector3fP’ : a member using-declaration or access declaration is illegal within a managed type

Any suggestions how to make my functions visible in C#?

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  1. Editorial Team
    Editorial Team
    2026-05-27T11:33:45+00:00Added an answer on May 27, 2026 at 11:33 am

    I think they key is in this claim from Managed Templates on MSDN:

    If a template is not instantiated, it’s not emitted in the metadata. If a template is instantiated, only referenced member functions will appear in metadata.

    That means that functions that aren’t used in the C++ code won’t be in the generated DLL and you won’t be able to use them from C#. To fix this, you could add a phony function to your C++ code, which references the function:

    void phony()
    {
        auto vec = gcnew Vector3fP();
        vec->foo();
    }
    
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