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Editorial Team
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Editorial Team
Asked: May 15, 20262026-05-15T15:36:40+00:00 2026-05-15T15:36:40+00:00

I’ve a regular expression that should validate if a string is composed by space-delimited

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I’ve a regular expression that should validate if a string is composed by space-delimited strings. The regular expression works well (ok it allows a empty space in the end … but that’s not he problem) but takes too long when the validation fails.

The regular expression is the following:

/^(([\w\-]+)( )?){0,}$/

When trying to validate with the string

"'this-is_SAMPLE-scope-123,this-is_SAMPLE-scope-456'"

it takes 2 seconds.

The tests were performed in ruby 1.9.2-rc1 and 1.8.7. But this is probably a general problem.

Any idea?

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  1. Editorial Team
    Editorial Team
    2026-05-15T15:36:41+00:00Added an answer on May 15, 2026 at 3:36 pm

    Your pattern causes catastrophic backtracking. The catastrophic part can be summarized to this:

    (.+)*
    

    The + and the * interacts in catastrophic ways in some engines.

    It’s unclear what you’re trying to match, exactly, but it may be something like this:

    ^[\w\-]+( [\w\-]+)*$
    

    This matches (as seen on rubular.com):

    hello world
    99 bottles of beer on the wall
    this_works_too
    

    and rejects:

    not like this, not like this
    hey what the &#@!
    too many    spaces
    

    Another option would be to use possessive quantifiers and/or atomic groupings in parts of the original pattern.

    References

    • regular-expressions.info/Possessive quantifiers and Atomic grouping

    Additional tips

    The {0,} repetition is usually written simply as *. You can also use non-capturing groups to improve performance, i.e. (?:pattern).

    References

    • regular-expressions.info/Brackets for Capturing and Repetition with Star and Plus

    Related questions

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