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Home/ Questions/Q 7667973
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Editorial Team
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Editorial Team
Asked: May 31, 20262026-05-31T15:14:21+00:00 2026-05-31T15:14:21+00:00

I’ve a table called data with columns ip, report_date, group, value . The primary

  • 0

I’ve a table called data with columns ip, report_date, group, value. The primary key is ip, report_date and group together.

When the table is empty and I run the statement below there is nothing inserted. What’s wrong with my statement?

When there is a match the record is updates according plan…

MERGE bc_data2 AS Target
USING (SELECT ip, report_date, group, value FROM bc_data2 As b
WHERE b.ip = '1.1.1.2'
AND b.report_date = '2/29/2012'
AND b.group = 'EPO-Client-Update') AS Source
ON (Target.ip = Source.ip
AND Target.frequency = Source.frequency
AND Target.report_date = Source.report_date
AND Target.service = Source.service
AND Target.proxy_service = Source.proxy_service
AND Target.proxy = Source.proxy
AND Target.service_group = Source.service_group)
WHEN MATCHED THEN
    UPDATE SET Target.value = Target.value + 1
WHEN NOT MATCHED BY Target THEN
    INSERT (ip, report_date, group, value)
    VALUES ('1.1.1.2', '2/29/2012', 'EPO-Client-Update', 119437142);
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  1. Editorial Team
    Editorial Team
    2026-05-31T15:14:22+00:00Added an answer on May 31, 2026 at 3:14 pm

    You don’t add any rows because your using clause is not returning any rows. Put your constants in the using clause with column aliases and use the fields in the when not matched

    Something like this with a couple of fields removed simplicity.

    merge bc_data2 as T
    using (select '1.1.1.2' as ip,
                  '2012-02-29' as report_date,
                  1194370142 as value) as S
    on T.ip = S.ip and
       T.report_date = S.report_date
    when matched then
      update set T.value = T.value + 1
    when not matched then
      insert (ip, report_date, value) 
        values(ip, report_date, value);
    
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