Question

I’ve a table invitation with coloumns toemail, fromemail, send

I need to print toemail & fromemail from all rows having valid send=1

This is the code that I’m using

<?php
$query = mysql_query("SELECT fromemail,toemail FROM invitations WHERE sent = 1");
if(mysql_num_rows($query)!=0)
{
    $row = mysql_fetch_assoc($query);
    echo $row['toemail'];
    echo $row['fromemail];
}
?>

But this prints only the first row which satisfying the condition.
Help me to get the php code please.
Thanks in advance.

Answer 1

Use this,

$query = mysql_query("SELECT fromemail,toemail FROM invitations WHERE sent = 1");
if(mysql_num_rows($query)!=0)
{
    while($row = mysql_fetch_assoc($query)) {
           echo $row['toemail'];
           echo $row['fromemail];
    }
}