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Home/ Questions/Q 7942185
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Editorial Team
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Editorial Team
Asked: June 3, 20262026-06-03T23:53:32+00:00 2026-06-03T23:53:32+00:00

I’ve always thought that it’s impossible for this to be null inside instance method

  • 0

I’ve always thought that it’s impossible for this to be null inside instance method body. Following simple program demonstrates that it is possible. Is this some documented behaviour?

class Foo
{
    public void Bar()
    {
        Debug.Assert(this == null);
    }
}

public static void Test()
{            
    var action = (Action)Delegate.CreateDelegate(typeof (Action), null, typeof(Foo).GetMethod("Bar"));
    action();
}

UPDATE

I agree with the answers saying that it’s how this method is documented. However, I don’t really understand this behaviour. Especially because it’s not how C# is designed.

We had gotten a report from somebody (likely one of the .NET groups
using C# (thought it wasn’t yet named C# at that time)) who had
written code that called a method on a null pointer, but they didn’t
get an exception because the method didn’t access any fields (ie
“this” was null, but nothing in the method used it). That method then
called another method which did use the this point and threw an
exception, and a bit of head-scratching ensued. After they figured it
out, they sent us a note about it.
We thought that being able to call a method on a null instance was a
bit weird. Peter Golde did some testing to see what the perf impact
was of always using callvirt, and it was small enough that we decided
to make the change.

http://blogs.msdn.com/b/ericgu/archive/2008/07/02/why-does-c-always-use-callvirt.aspx

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-03T23:53:35+00:00Added an answer on June 3, 2026 at 11:53 pm

    Because you’re passing null into the firstArgument of Delegate.CreateDelegate

    So you’re calling an instance method on a null object.

    http://msdn.microsoft.com/en-us/library/74x8f551.aspx

    If firstArgument is a null reference and method is an instance method,
    the result depends on the signatures of the delegate type type and of
    method:

    If the signature of type explicitly includes the hidden first
    parameter of method, the delegate is said to represent an open
    instance method. When the delegate is invoked, the first argument in
    the argument list is passed to the hidden instance parameter of
    method.

    If the signatures of method and type match (that is, all parameter
    types are compatible), then the delegate is said to be closed over a
    null reference. Invoking the delegate is like calling an instance
    method on a null instance, which is not a particularly useful thing to
    do.

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