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Home/ Questions/Q 7535255
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Editorial Team
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Editorial Team
Asked: May 30, 20262026-05-30T06:15:47+00:00 2026-05-30T06:15:47+00:00

I’ve attached files on bottom of the page (before body): <script src=http://code.jquery.com/jquery-1.6.4.min.js></script> <script src=/js/mobile.js></script>

  • 0

I’ve attached files on bottom of the page (before body):

<script src="http://code.jquery.com/jquery-1.6.4.min.js"></script>
<script src="/js/mobile.js"></script>
<script src="http://code.jquery.com/mobile/1.0.1/jquery.mobile-1.0.1.min.js"></script>

in mobile.js is code like that:

$(document).ready(function(){
    console.log('test')
});

and firebug returns me ‘test’ twice, why?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-30T06:15:48+00:00Added an answer on May 30, 2026 at 6:15 am

    It is recommended to use the pageInit event with jQuery mobile as opposed to $(document).ready. See this page for more details: jQuery Mobile Docs – Events.

    The code you could use:

    $("#yourPage").live('pageinit', function() {
        console.log('test');
    });
    

    That may fix your problem.

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