Question

I’ve been battling with this for a while, I’m not familiar with PHP syntax, here’s my code:

    $eventArray = array($this->ReturnLastRecordId() + 1, $managerid, $title, $description, $category, $address, $location, $startdate, $starttime, $enddate, $endtime, $price, $endofticketdate, $totalseats,  $totalseats);
    $sql = "INSERT INTO event (eventid, managerid, title, description, category, address, location, startdate, starttime, enddate, endtime, price, endofticketdate, totalseats, totalseats)";
    $data->StoreData($eventArray, $sql);

In the function:

public function StoreData($dataArray, $sqlquery)
    {

        include 'config.php';

        $i = count($dataArray);
        echo $i;
        switch ($i) {
            case 15:
            mysql_query($sqlquery . "VALUES (" . '$arraydata[0]' ,   '$arraydata[1]',  '$arraydata[2]',  '$arraydata[3]', '$arraydata[4]', '$arraydata[5]', '$arraydata[6]', '$arraydata[7]', '$arraydata[8]', '$arraydata[9]',  '$arraydata[10]', '$arraydata[11]', '$arraydata[12]',  '$arraydata[13]',  '$arraydata[14]' . ")", $con) or die (mysql_error());
            mysql_close($con);
                break;

        }
    }

Obviously I’ve checked the number of parameters multiple times, including the database, but still the parameter count get thrown :(.

Answer 1

You are not concatenating the SQL string. Your code passes multiple separate PHP function parameters.

The most lazy fix would be:

 $values = implode("','", $arraydata);

 mysql_query("$sqlquery VALUES ('$values')");

I would advise that you enclose the whole single string that mysql_query expects in double quotes, and then use string interpolation within. Avoid manual . concatenation.