I’ve been butting my head against this problem in an assignment I’ve been working on, and can’t seem to get it to work at all. I wrote a little test class to demonstrate what I’m trying to do, and hopefully someone can explain what I need to do.
//Tester class
#include <iostream>
using namespace std;
template <typename T>
class Tester
{
typedef void (Tester<T>::*FcnPtr)(T);
private:
T data;
void displayThrice(T);
void doFcn( FcnPtr fcn );
public:
Tester( T item = 3 );
void function();
};
template <typename T>
inline Tester<T>::Tester( T item )
: data(item)
{}
template <typename T>
inline void Tester<T>::doFcn( FcnPtr fcn )
{
//fcn should be a pointer to displayThrice, which is then called with the class data
fcn( this->data );
}
template <typename T>
inline void Tester<T>::function()
{
//call doFcn with a function pointer to displayThrice()
this->doFcn( &Tester<T>::displayThrice );
}
template <typename T>
inline void Tester<T>::displayThrice(T item)
{
cout << item << endl;
cout << item << endl;
cout << item << endl;
}
-and here’s main:
#include <iostream>
#include "Tester.h"
using namespace std;
int main()
{
Tester<int> test;
test.function();
cin.get();
return 0;
}
-and lastly, my compiler errors (VS2010)
c:\users\name\documents\visual studio 2010\projects\example\example\tester.h(28): error C2064: term does not evaluate to a function taking 1 arguments
1> c:\users\name\documents\visual studio 2010\projects\example\example\tester.h(26) : while compiling class template member function 'void Tester<T>::doFcn(void (__thiscall Tester<T>::* )(T))'
1> with
1> [
1> T=int
1> ]
1> c:\users\name\documents\visual studio 2010\projects\example\example\tester.h(21) : while compiling class template member function 'Tester<T>::Tester(T)'
1> with
1> [
1> T=int
1> ]
1> c:\users\name\documents\visual studio 2010\projects\example\example\example.cpp(7) : see reference to class template instantiation 'Tester<T>' being compiled
1> with
1> [
1> T=int
1> ]
Hopefully, my comments in the Tester class will tell you what I’m trying to do. Thank you for taking the time to look at this!
You’re not calling the member function pointer corrently; it requires the use of a special operator called the pointer-to-member operator.