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Home/ Questions/Q 1093705
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Editorial Team
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Editorial Team
Asked: May 16, 20262026-05-16T23:51:49+00:00 2026-05-16T23:51:49+00:00

I’ve been coding a bit of Javascript to place a ducky randomly on this

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I’ve been coding a bit of Javascript to place a ducky randomly on this page.

I wanted to make it hide on the side of objects (like the posts), but I ended up having to hardcode quite a bit of it, since I couldn’t get a way to properly retrieve the real position of relative objects with Chrome. I read quite a few things about it, and used the recursive offsetParent way, but didn’t get any good results.

The last bit of code I tried was this:

 var getPost = function (obj) {
    var pos = {'x':0,'y':0};
    if(obj.offsetParent) {
        while(1) {
          pos.x += obj.offsetLeft;
          pos.y += obj.offsetTop;
          if(!obj.offsetParent) {
            break;
          }
          obj = obj.offsetParent;
        }
    } else if(obj.x) {
        pos.x += obj.x;
        pos.y += obj.y;
    }
    return pos;
  }

This code doesn’t work on Chrome, except on objects with an absolute position (set with CSS).

Is there a good, cross-browser way to achieve this?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-16T23:51:50+00:00Added an answer on May 16, 2026 at 11:51 pm

    Alright, my problem was somewhere else. This is what I was doing to call the function:

    var allPosts = document.getElementsByClassName('post-outer');
    
    for (post in allPosts) {
       console.log('Post has position '+getPos(post));
    }
    

    You can tell I’m not so used to Javascript’s recursive behavior in the for loop, so the following code actually fixes my issue:

    var allPosts = document.getElementsByClassName('post-outer');
    
    for (var i=0, len=allPosts.length; i<len; ++i ){
      console.log('Post position is '+getPos(allPosts[i]).y);
    }
    

    Thanks all for your help 🙂

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