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Home/ Questions/Q 6561143
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Editorial Team
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Editorial Team
Asked: May 25, 20262026-05-25T13:33:04+00:00 2026-05-25T13:33:04+00:00

i’ve been doing a login form by JSON encode, my code is like this

  • 0

i’ve been doing a login form by JSON encode, my code is like this :

public void onClick(View v) {
if(v==login){
login();
}
}

public void login(){

           String url_select = "http://ipadress/select.php";

           HttpClient httpClient = new DefaultHttpClient();
           HttpPost httpPost = new HttpPost(url_select);

           //parameter
           ArrayList<NameValuePair> param = new ArrayList<NameValuePair>();

           try {
              //add parameter
               httpPost.setEntity(new UrlEncodedFormEntity(param));

             HttpResponse httpRespose = httpClient.execute(httpPost);
             HttpEntity httpEntity = httpRespose.getEntity();

             //read content
             InputStream in = httpEntity.getContent();
             BufferedReader read = new BufferedReader(new InputStreamReader(in));

             String content = "";
             String line = "";

             while((line = read.readLine())!=null){
                content += line;
             }

             Log.d("ADBUG", "content: "+content);


             //json
             if(!content.equals("null")){

                try {
                   JSONArray jArr = new JSONArray(content);
                   String uname="";
                   String passw="";
                   String idx="";
                   for(int i=0;i<jArr.length();i++){
                      JSONObject jObj = jArr.getJSONObject(i);
                      String id = jObj.getString("_id");
                      String username = jObj.getString("username");
                      String password = jObj.getString("password");
                      idx += id+"\n";
                      uname += username+"\n";
                      passw += password+"\n";
                   }

                    if(user.getText().toString().equals(uname) && pass.getText().toString().equals(passw)){
                        Intent a;
                        a = new Intent(this, WelcomeMenu.class);
                        startActivity(a);
                    }


                } catch (JSONException e) {
                   // TODO Auto-generated catch block
                   e.printStackTrace();
                }

             }else{
                Toast.makeText(this, "Error", Toast.LENGTH_LONG).show();
             }

          } catch (ClientProtocolException e) {
             // TODO Auto-generated catch block
             e.printStackTrace();
          } catch (IOException e) {
             // TODO Auto-generated catch block
             e.printStackTrace();
          }
       }

select.php :

<?php
include_once("koneksi.php");
$number_id= $_REQUEST['number_id'];

if($nomor_id){
   $sqlString = "select * from login where _id=$number_id";
}else{
   $sqlString = "select * from login";
}

$rs = mysql_query($sqlString);

if($rs){
   while($objRs = mysql_fetch_assoc($rs)){
      $output[] = $objRs;
   }

   echo json_encode($output);
}

mysql_close();

?>

the problem is i can’t login, i’ve been insert username and password on my sql already, buat i can’t login, anyone can help me? thanks before

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-25T13:33:04+00:00Added an answer on May 25, 2026 at 1:33 pm

    Where do you fill the parameters?

           ArrayList<NameValuePair> param = new ArrayList<NameValuePair>();
    
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