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Home/ Questions/Q 6628259
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Editorial Team
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Editorial Team
Asked: May 25, 20262026-05-25T22:06:35+00:00 2026-05-25T22:06:35+00:00

I’ve been doing (in C) char array[100]; if (array == NULL) something; which is

  • 0

I’ve been doing (in C)

char array[100];
if (array == NULL)
   something;

which is very wrong (which I have finally learned since my program doesn’t work). What is the equivalent where I could test a new array to see if nothing has been put in it yet?

Also, how do you make an array empty/clean it out?

I know there are other posts out on this topic out there, but I couldn’t find a straightforward answer.

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  1. Editorial Team
    Editorial Team
    2026-05-25T22:06:35+00:00Added an answer on May 25, 2026 at 10:06 pm

    An array declared with

    char array[100]
    

    always has 100 characters in it.

    By “cleaning out” you may mean assigning a particular character to each slot, such as the character '\0'. You can do this with a loop, or one of several library calls to clear memory or move memory blocks.

    Look at memset — it can “clear” or “reset” your array nicely.

    If you are working with strings, with are special char arrays terminated with a zero, then in order to test for an empty array, see this SO question. Otherwise if you have a regular character array not intended to represent text, write a loop to make sure all entries in the array are your special blank character, whatever you choose it to be.

    You can also declare your character array like so:

    char* array = malloc(100);
    

    or even

    char* array = NULL;
    

    but that is a little different. In this case the array being NULL means “no array has been allocated” which is different from “an array has been allocated but I have not put anything in it yet.”

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