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Home/ Questions/Q 6655087
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T01:28:14+00:00 2026-05-26T01:28:14+00:00

I’ve been experimenting with building an Outlook 2010 addin in C#, using Visual Studio

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I’ve been experimenting with building an Outlook 2010 addin in C#, using Visual Studio 2008. I am able to obtain a Microsoft.Office.Interop.Word.DocumentClass object from a Microsoft.Office.Interop.Outlook.Inspector object, which represents the e-mail being currently edited. I understand that this DocumentClass is used in various other contexts too (usually for Microsoft Word extensions, unsurprisingly).

That class helpfully has a property called WordOpenXML, which seems to be an XML representation of all the files constituting the the .docx package which would be saved to disk when saving this Word document as a .docx.

One way this property would be very useful is if it could be converted into a System.IO.Packaging.Package object in memory; ie. deserialize it. Does anyone know whether there is an easy way to do this, or do I need to write some XML parsing code to do it manually?

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  1. Editorial Team
    Editorial Team
    2026-05-26T01:28:15+00:00Added an answer on May 26, 2026 at 1:28 am

    I ended up modifying some code I found online to create a method which converts WordOpenXML to a Package, which is saved to disk:

    using System;
    using System.Xml;
    using System.Xml.XPath;
    using System.Text;
    using System.IO;
    using System.IO.Packaging;
    
    // [...]
    // Call like this: createPackageFromWordOpenXML(wordEditor.WordOpenXML, @"C:\outputFiles\testOut.docx");
    
    /// <summary>
    /// Creates a ZIP package (ie. Word's .docx format) from a WordOpenXML string, which is saved to the file at the path specified.
    /// </summary>
    /// <param name="wordOpenXML">The WordOpenXML string to get the ZIP package data from.</param>
    /// <param name="filePath">The path of the file to save the ZIP package to.</param>
    private void createPackageFromWordOpenXML(string wordOpenXML, string filePath)
    {
        string packageXmlns = "http://schemas.microsoft.com/office/2006/xmlPackage";
        Package newPkg = System.IO.Packaging.ZipPackage.Open(filePath, FileMode.Create);
    
        try
        {
            XPathDocument xpDocument = new XPathDocument(new StringReader(wordOpenXML));
            XPathNavigator xpNavigator = xpDocument.CreateNavigator();
    
            XmlNamespaceManager nsManager = new XmlNamespaceManager(xpNavigator.NameTable);
            nsManager.AddNamespace("pkg", packageXmlns);
            XPathNodeIterator xpIterator = xpNavigator.Select("//pkg:part", nsManager);
    
            while (xpIterator.MoveNext())
            {
                Uri partUri = new Uri(xpIterator.Current.GetAttribute("name", packageXmlns), UriKind.Relative);
    
                PackagePart pkgPart = newPkg.CreatePart(partUri, xpIterator.Current.GetAttribute("contentType", packageXmlns));
    
                // Set this package part's contents to this XML node's inner XML, sans its surrounding xmlData element.
                string strInnerXml = xpIterator.Current.InnerXml
                    .Replace("<pkg:xmlData xmlns:pkg=\"" + packageXmlns + "\">", "")
                    .Replace("</pkg:xmlData>", "");
                byte[] buffer = Encoding.UTF8.GetBytes(strInnerXml);
                pkgPart.GetStream().Write(buffer, 0, buffer.Length);
            }
    
            newPkg.Flush();
        }
        finally
        {
            newPkg.Close();
        }
    }
    
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