I’ve been experimenting with function types in C++. Note that I don’t mean pointer-to-function types like:
typedef void (*voidFuncPtr)();
but the more exotic:
typedef void (voidFunc)();
I didn’t expect the following code to compile, but surprisingly it did:
template<voidFunc func>
class funcClass
{
public:
void call() { func(); };
};
void func()
{ }
void Test()
{
funcClass<func> foobar;
foobar.call();
}
however, if I try adding the following to funcClass:
voidFuncPtr get() { return &func; }
I get the error Address expression must be an lvalue or a function designator
My first question here is: what kind of black magic is the compiler using to pretend that a func type is something it can actually pass around an instance of? Is it just treating it like a reference? Second question is: if it can even be called, why can’t the address of it be taken? Also, what are these non-pointer-to function types called? I only discovered them because of boost::function, and have never been able to find any documentation about them.
§14.1.4 of the Standard says:
And §14.1.6 says
So that explains the two behaviours you are seeing.
Note that
funcis the same as&func(§14.3.2.1):So it’s just a function pointer.