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Home/ Questions/Q 7059993
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Editorial Team
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Editorial Team
Asked: May 28, 20262026-05-28T04:17:57+00:00 2026-05-28T04:17:57+00:00

I’ve been fighting this for a while, seems I’m close but not quite there.

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I’ve been fighting this for a while, seems I’m close but not quite there. I have a column in a database that looks like this:

<document>
<items>
<item name="one">one is the first number</item>
<item name="two">two is the second number</item>
</items>
</document>

In this example I need to query and return ‘two is the second number’. I’d also like to do this without creating a temp table. Currently I have:

create table #test (item1 xml)
insert into #test (item1) 
values ('<document> <items> <item name="one">one is the first number</item> <item name="two">two is the second number</item> </items> </document>')

select item1.value('(/document/items/item)[2]', 'nvarchar(max)') from #test
select item1.query('/document/items/item[@name="two"]') from #test

The first select returns the correct value but I need to know that it’s the 2nd ‘index’
The second returns what I want but it returns the entire node two..

What am I missing? And, is there a simple way to use the XML without converting to a temp table?

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  1. Editorial Team
    Editorial Team
    2026-05-28T04:17:57+00:00Added an answer on May 28, 2026 at 4:17 am

    I’d also like to do this without creating a temp table

    You can use a variable with datatype XML.

    declare @xml xml
    
    set @xml = 
    '<document>
      <items>
        <item name="one">one is the first number</item>
        <item name="two">two is the second number</item>
      </items>
    </document>'
    
    select @xml.value('(/document/items/item[@name="two"])[1]', 'nvarchar(max)')
    

    Or you can cast your string to XML in the query.

    select cast(
                '<document>
                  <items>
                    <item name="one">one is the first number</item>
                    <item name="two">two is the second number</item>
                  </items>
                </document>' as xml
               ).value('(/document/items/item[@name="two"])[1]', 'nvarchar(max)')
    

    Your first query uses .value() which is correct and your second query has the correct XQuery expression. When using .value() you need to use a XQuery expression that returns a single value. This will give you all item nodes where @name is two /document/items/item[@name="two"]). Adding [1] at the end makes sure that you will only get the first occurrence in the XML where @name is two.

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