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Editorial Team
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Editorial Team
Asked: May 11, 20262026-05-11T21:18:58+00:00 2026-05-11T21:18:58+00:00

I’ve been given a cheap, brandless 2GB flash drive. As I have a bigger

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I’ve been given a cheap, brandless 2GB flash drive. As I have a bigger flash drive, I have decided to use it for testing flash technology robustness.

I plan to write 1’s all over the drive, check for correctness, write 0’s, check and so on. I’ll log the results, and seek for failures later.

I am looking for the most resource-saving technique for doing that. My current strategy includes using linux dd command for writing and reading, and comparing the result to a file of ones and zeros. Another approach would be writing ones and zeros to the drive, and calculating the md5 of its contents. This is a simple trade-off between extensive IO reads and high CPU usage; I guess I’ll simply measure the running time of each method and decide.

Are there any better, more elegant ways of doing this?

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  1. Editorial Team
    Editorial Team
    2026-05-11T21:18:58+00:00Added an answer on May 11, 2026 at 9:18 pm

    Pick a random 32 bit number. Write that in every block. Read that from every block. New 32 bit number. Run the drive again. Hash algorithms like MD5 are CPU intensive. Since you know exactly the pattern and are just testing that the drive doesn’t screw up the bits, simple direct comparison is the best approach. Don’t use DD… write direct from a language like C or Perl (if there were ever apples standing next to oranges…)

    No need to have a comparison file either… the pattern fits in memory. In fact, the whole test probably fits in the CPU cache if done neatly, but the flash drive will obviously be a bottleneck anyway. Find a number that isn’t right, you know you’ve got your bad block.

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