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Home/ Questions/Q 3303972
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Editorial Team
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Editorial Team
Asked: May 17, 20262026-05-17T21:00:45+00:00 2026-05-17T21:00:45+00:00

I’ve been looking at the GCC docs for defining macros and it looks like

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I’ve been looking at the GCC docs for defining macros and it looks like what I want isn’t possible, but I figure if it is, someone here would know.

What I want to do is define this macro:

synchronized(x) {
  do_thing();
}

Which expands to:

{
    pthread_mutex_lock(&x);
    do_thing();
    pthread_mutex_unlock(&x);
}

In C++ I could just make a SynchronizedBlock object that gets the lock in its constructor and unlocks in the destructor, but I have no idea how to do it in C.

I realize I could use a function pointer in the form synchronized(x, &myfunction);, but my goal is to make some C code look as much like Java as possible. And yes, I know this is evil.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-17T21:00:46+00:00Added an answer on May 17, 2026 at 9:00 pm

    EDIT: Changed to nategoose’s version

    #define synchronized(lock) \
    for (pthread_mutex_t * i_#lock = &lock; i_#lock; \
         i_#lock = NULL, pthread_mutex_unlock(i_#lock)) \
        for (pthread_mutex_lock(i_#lock); i_#lock; i_#lock = NULL)
    

    And you can use it like this:

    synchronized(x) {
        do_thing(x);
    }
    

    Or even without braces

    synchronized(x)
        do_thing();
    
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