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Home/ Questions/Q 552283
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T11:28:58+00:00 2026-05-13T11:28:58+00:00

I’ve been looking into doing inheritance in JavaScript the correct prototypal way, according to

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I’ve been looking into doing inheritance in JavaScript the correct prototypal way, according to Douglas Crockford: http://javascript.crockford.com/prototypal.html

He writes: “So instead of creating classes, you make prototype objects, and then use the object function to make new instances”

I figured this was the way to do it:

var objA = {
    func_a : function() {
        alert('A');
    }
};

var objB = Object.create(objA);
objB.func_a = function() {
   alert('B');
}
objB.func_b = function() {
};


var objA_instance1 = Object.create(objA);
var objA_instance2 = Object.create(objA);
var objB_instance1 = Object.create(objB);
var objB_instance2 = Object.create(objB);
etc...

But wouldn’t this mean that there are now four instances of func_a (since it’s isn’t part of objA.prototype, it’s just “inside” it), or am I not understanding this correctly?

Also, is there any way I can reach the overridden function of a function (for example call objA.func_a inside objB.func_a)?

Thanks in advance.

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  1. Editorial Team
    Editorial Team
    2026-05-13T11:28:59+00:00Added an answer on May 13, 2026 at 11:28 am

    You’re confusing the prototype property of constructor functions with the internal [[Prototype]] property of objects, which is inaccessible (FF makes it available as __proto__); using Object.create() sets this internal property to its argument, so objA and objB will be the actual prototypes of your ‘instance’ objects, ie no function objects will be duplicated.

    To call the overridden functions, access them via eg objA.func_a and use call() or apply() to use them on the specific instances, eg

    objB.func_a = function() {
        objA.func_a.call(this); // call overridden method with current `this`
    };
    
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