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Home/ Questions/Q 852995
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Editorial Team
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Editorial Team
Asked: May 15, 20262026-05-15T07:41:13+00:00 2026-05-15T07:41:13+00:00

I’ve been playing around with references (I’m still having issues in this regard). 1-

  • 0

I’ve been playing around with references (I’m still having issues in this regard).

1- I would like to know if this is an acceptable code:

int & foo(int &y)
{
    return y;  // is this wrong?
}

int main()
{
    int x = 0;    
    cout << foo(x) << endl;

    foo(x) = 9;   // is this wrong?
    cout << x << endl;

    return 0;
}

2- Also this is from an exam sample:

Week & Week::highestSalesWeek(Week aYear[52])
{
  Week max = aYear[0];
  for(int i = 1; i < 52; i++)
  {
    if (aYear[i].getSales() > max.getSales())
      max = aYear[i];
  }
  return max;
}

It asks about the mistake in this code, also how to fix it.

My guess is that it return a local reference.
The fix is:

Week & max = aYear[0];

Is this correct/enough?

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  1. Editorial Team
    Editorial Team
    2026-05-15T07:41:13+00:00Added an answer on May 15, 2026 at 7:41 am

    The first one is correct.

    For the second one, there are infinite number of solutions :), but this would be mine:

    Week Week::highestSalesWeek(Week aYear[52]) // return a copy of the week
    { 
      Week max = aYear[0]; 
      for(int i = 1; i < 52; i++) 
      { 
        if (aYear[i].getSales() > max.getSales()) max = aYear[i]; 
      } 
      return max; 
    } 
    

    If max is a reference, you would modify the first element of aYear everytime you do:

    max = aYear[i]
    

    Also, you could use a pointer to return a reference to the week:

    Week & Week::highestSalesWeek(Week aYear[52])
    { 
      Week* max = &aYear[0]; 
      for(int i = 1; i < 52; i++) 
      { 
        if (aYear[i].getSales() > max->getSales()) max = &aYear[i]; 
      } 
      return *max; 
    } 
    
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