Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 7059111
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 28, 20262026-05-28T04:11:35+00:00 2026-05-28T04:11:35+00:00

I’ve been recently working towards learning a bit of assembly and I’m currently stumped

  • 0

I’ve been recently working towards learning a bit of assembly and I’m currently stumped on an exercise which requires me to find the maximum number of a list of long values.

The code is as follows:

.section .data
    data_items: .long 200, 201, 101, 10, 0
    min_val: .long 0x8000000000000000 # MIN_VALUE in long

.section .text
.global _start

    _start:
        movl $0, %edi   # init counter to 0
        movl min_val, %ebx
    start_loop:
        cmpl $0, %eax
        je loop_exit    # go to end if 0 encountered

        incl %edi
        movl data_items(,%edi,4), %eax
        cmpl %ebx, %eax
        jle start_loop  # if new value < max value in ebx, read next element

        movl %eax, %ebx
        jmp start_loop

    loop_exit:
        movl $1, %eax
        int $0x80

Two problems with this code:

  • When trying to assemble the code, I get the message: Warning: value 0x8000000000000000 truncated to 0x0
  • If I rewrite my code in an alternative logic (one which doesn’t require min_value variable), any value greater than 255 in the list of data_items is truncated or returned as value % 256 even though the range of .long should be much larger?

Can anyone help me understand what I’m doing wrong?

EDIT: After changes, the code looks like below. Note how maximum in this case turns out to be 145 instead of 401.

.section .data
    data_items: .long 401, 201, 101, 10, 0
    max_val: .long 0x80000000

.section .text
.global _start

    _start:
        movl $0, %edi   # init counter to 0
        movl max_val, %ebx
    start_loop:
        movl data_items(,%edi,4), %eax
        cmpl $0, %eax
        je loop_exit    # go to end if 0 encountered

        incl %edi

        cmpl %ebx, %eax
        jle start_loop  # if new value < max value in ebx, read next element

        movl %eax, %ebx
        jmp start_loop

    loop_exit:
        movl $1, %eax
        int $0x80
  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-28T04:11:35+00:00Added an answer on May 28, 2026 at 4:11 am

    First of all, 0x8000000000000000 doesn’t even fit in a long, it’s a long long. A long -1 is 0xffffffff.

    As for the other point, I can’t comment on code you haven’t posted.

    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

I have a jquery bug and I've been looking for hours now, I can't
link Im having trouble converting the html entites into html characters, (&# 8217;) i
I am trying to understand how to use SyndicationItem to display feed which is
I used javascript for loading a picture on my website depending on which small
I have a string like this: La Torre Eiffel paragonata all&#8217;Everest What PHP function
I would like to run a str_replace or preg_replace which looks for certain words
I want use html5's new tag to play a wav file (currently only supported
I'm parsing an RSS feed that has an &#8217; in it. SimpleXML turns this
I have a text area in my form which accepts all possible characters from
Seemingly simple, but I cannot find anything relevant on the web. What is the

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.