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Home/ Questions/Q 8066707
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Editorial Team
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Editorial Team
Asked: June 5, 20262026-06-05T12:05:28+00:00 2026-06-05T12:05:28+00:00

I’ve been searching around before asking this. I have Django template, which inputs a

  • 0

I’ve been searching around before asking this.

I have Django template, which inputs a water account number, a beginning date, and an ending date. The dates define a search range, and are in mm/dd/yyyy format.

I’d like to convert these dates into a Python format, so I can find the difference between them. I’m aware of date and datetime objects, and I know I can parse — for example — 05/01/2012 — and create a date object from that.

However, I’m interested in a better way to this, like converting the “05/01/2012” directly for start and end date range values, and then taking the delta between those Python date objects.

Thank you.

Edit:
This is what I’m using to calculate the delta:

d1 and d2 are date strings in the form: mm/dd/yyyy.
def time_delta(d1, d2):
    dd1   = datetime.strptime(d1, "%m/%d/%Y").date()
    dd2   = datetime.strptime(d2, "%m/%d/%Y").date()
    delta = dd2 - dd1
    return delta.days
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  1. Editorial Team
    Editorial Team
    2026-06-05T12:05:30+00:00Added an answer on June 5, 2026 at 12:05 pm

    Maybe something like this?

    from datetime import *
    d1 = datetime.strptime('05/01/2012', "%d/%m/%Y").date()
    d2 = datetime.strptime('06/01/2012', "%d/%m/%Y").date()
    delta = d2 - d1
    print(delta.days)
    
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