Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 8699313
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: June 13, 20262026-06-13T01:55:06+00:00 2026-06-13T01:55:06+00:00

i’ve been searching SO for a while and found nothing related to this. We

  • 0

i’ve been searching SO for a while and found nothing related to this.

We use heavily the dynamic approach for most of our queries like this:

Declare @ContactId VarChar(8000)

Select @ContactId = '1'

Select * 
From Person.Contact
Where 1 = 1 And 
Case When Len(Ltrim(Rtrim(@ContactId))) = 0 Then 1 Else ContactID End =
Case When Len(Ltrim(Rtrim(@ContactId))) = 0 Then 1 Else @ContactId End

This way the query gets filtered dynamically if there’s a value on the parameter

But the problem comes when trying the same stuff with several IDs like so:

Declare @ContactId VarChar(8000)

Select @ContactId = '1,2,3'

Select * 
From Person.Contact
Where 1 = 1 And 
Case When Len(Ltrim(Rtrim(@ContactId))) = 0 Then 1 Else ContactID End In (
Select Case When Len(Ltrim(Rtrim(@ContactId))) = 0 Then 1 Else ( Select id From dbo.SplitString(@ContactId,',') ) End )

Sql throws an error “Subquery returned more than 1 value. This is not permitted when the subquery follows =, !=, <, <= , >, >= or when the subquery is used as an expression.”

that’s totally normal and expected, my question is:

Is there a way to dynamically do this kind of filtering ?

The solution we use is this:

Declare @Table Table(
    Col1    Int,
    Col2    Int,
    Col3    Int
)

Insert @Table
Select Col1, Col2, Col3
From Person.Contact
Where [many filters except the in clause filters]

If Len(Ltrim(RTrim(@ContactId))) > 0
    Select * 
    From @Table
    Where ContactId In ( Select Id From dbo.SplitString(@ContactId, ',') )
Else 
Select *
From @Table

But it’s not an option when the query is massive and feeding a table variable is overkill for this. Hope i made my point and someone is kind enough to help me find a solution to this.

PS: Using sp_ExecuteSql is not an option in this scenario either, sorry.

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-06-13T01:55:07+00:00Added an answer on June 13, 2026 at 1:55 am

    How you should do this is with a table parameter.

    But if you want to persist in this approach.

    Declare @ContactId VarChar(8000) 
    
    Select @ContactId = '1,2,3'
    Select *  
    From Person.Contact 
    where ',' + @contactID + ',' like '%,'+convert(varchar(50),contactid)+',%'
    
    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

I have a string like this: La Torre Eiffel paragonata all&#8217;Everest What PHP function
I'm parsing an RSS feed that has an &#8217; in it. SimpleXML turns this
Let's say I'm outputting a post title and in our database, it's Hello Y&#8217;all
I have a jquery bug and I've been looking for hours now, I can't
link Im having trouble converting the html entites into html characters, (&# 8217;) i
For some reason, after submitting a string like this Jack’s Spindle from a text
I am trying to understand how to use SyndicationItem to display feed which is
this is what i have right now Drawing an RSS feed into the php,
I have this code to decode numeric html entities to the UTF8 equivalent character.
I want use html5's new tag to play a wav file (currently only supported

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.