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Home/ Questions/Q 835033
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Editorial Team
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Editorial Team
Asked: May 15, 20262026-05-15T04:45:44+00:00 2026-05-15T04:45:44+00:00

I’ve been struggling to figure out how to best do this regular expression. Here

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I’ve been struggling to figure out how to best do this regular expression.

Here are my requirements:

  • Up to 8 characters
  • Can only be alphanumeric
  • Can only contain up to three alpha characters [a-z] (zero alpha characters are valid to)

Any ideas would be appreciated.

This is what I’ve got so far, but it only looks for contiguous letter characters:

^(\d|([A-Za-z])(?!([A-Za-z]{3,}))){0,8}$
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  1. Editorial Team
    Editorial Team
    2026-05-15T04:45:44+00:00Added an answer on May 15, 2026 at 4:45 am

    I’d write it like this:

    ^(?=[a-z0-9]{0,8}$)(?:\d*[a-z]){0,3}\d*$
    

    It has two parts:

    • (?=[a-z0-9]{0,8}$)
      • Looksahead and matches up to 8 alphanumeric to the end of the string
    • (?:\d*[a-z]){0,3}\d*$
      • Essentially allowing injection of up to 3 [a-z] among \d*

    Rubular

    On rubular.com

    12345678    // matches
    123456789
    @(#*@$
    12345       // matches
    abc12345
    abcd1234
    12a34b5c    // matches
    12ab34cd
    123a456     // matches
    

    Alternatives

    I do think regex is the best solution for this, but since the string is short, it would be a lot more readable to do this in two steps as follows:

    • It must match [a-z0-9]{0,8}
    • Then, delete all \d
      • The length must now be <= 3
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