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Home/ Questions/Q 8003427
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Editorial Team
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Editorial Team
Asked: June 4, 20262026-06-04T16:38:48+00:00 2026-06-04T16:38:48+00:00

I’ve been testing a bit with using $.Deferred() in jQuery lately and got a

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I’ve been testing a bit with using $.Deferred() in jQuery lately and got a question. While deferred and promises are great for ajaxcalls that’s only intended to run once, I also got a form for adding new users that posts with ajax needs to be runnable multiple times. Now this crashes with the binary(ish) state of a deferred/promise as once they’re resolved or rejected it’ll keep that state. So my questions are:

-Can I use deferred for a task that will be called multiple times?
-If possible, is it recommended to use deferred for this or should I stick to the old method with just using the success/error callbacks of $.ajax?

Here some code I got together for posting the form, which works great once, but not multiple times.

var submittingUser = new $.Deferred();
var savingUser = submittingUser.pipe(function(data) {
    return $.post('ajax.php', data);
});

$("#add_new_user").click(function() {
    var data = $("#add_user_form").serialize();
    submittingUser.resolve(data);
    return false;
});

savingUser.then(function() {
    //Success
}, function() {
    //Failed
});
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  1. Editorial Team
    Editorial Team
    2026-06-04T16:38:49+00:00Added an answer on June 4, 2026 at 4:38 pm

    It makes no sense to use a deferred in that manner. A deferred represents an action; you cannot use it as an event emitter. You use a deferred when you start an asynchronous action, and want to do something when that action succeeds or fails.

    $.post() returns a promise (actually it returns a jqXHR instance, which however implements the promise interface), so you can do $.post(...).fail(handleFailure).done(handleSuccess). But you cannot use a deferred to run some code every time something happens.

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