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Home/ Questions/Q 749263
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Editorial Team
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Editorial Team
Asked: May 14, 20262026-05-14T14:24:53+00:00 2026-05-14T14:24:53+00:00

I’ve been trying to construct a ruby regex which matches trailing spaces – but

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I’ve been trying to construct a ruby regex which matches trailing spaces – but not indentation placeholders – so I can gsub them out.

I had this /\b[\t ]+$/ and it was working a treat until I realised it only works when the line ends are [a-zA-Z]. 🙁 So I evolved it into this /(?!^[\t ]+)[\t ]+$/ and it seems like it’s getting better, but it still doesn’t work properly. I’ve spent hours trying to get this to work to no avail. Please help.

Here’s some text test so it’s easy to throw into Rubular, but the indent lines are getting stripped so it’ll need a few spaces and/or tabs. Once lines 3 & 4 have spaces back in, it shouldn’t match on lines 3-5, 7, 9.

some test test  
some test test      


  some other test (text)
  some other test (text)  
  likely here{ dfdf }
  likely here{ dfdf }        
  and this ;
  and this ;  

Alternatively, is there an simpler / more elegant way to do this?

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  1. Editorial Team
    Editorial Team
    2026-05-14T14:24:53+00:00Added an answer on May 14, 2026 at 2:24 pm

    If you’re using 1.9, you can use look-behind:

    /(?<=\S)[\t ]+$/
    

    but unfortunately, it’s not supported in older versions of ruby, so you’ll have to handle the captured character:

    str.gsub(/(\S)[\t ]+$/) { $1 }
    
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