Question

I’ve been trying to get a table row with this query:

SELECT * FROM `table` WHERE `field` LIKE "%\u0435\u0442\u043e\u0442%"

Field itself:

Field                                     
--------------------------------------------------------------------
\u0435\u0442\u043e\u0442 \u0442\u0435\u043a\u0441\u0442 \u043d\u0430

Although I can’t seem to get it working properly.
I’ve already tried experimenting with the backslash character:

LIKE "%\\u0435\\u0442\\u043e\\u0442%"
LIKE "%\\\\u0435\\\\u0442\\\\u043e\\\\u0442%"

But none of them seems to work, as well.

I’d appreciate if someone could give a hint as to what I’m doing wrong.
Thanks in advance!

---

EDIT

Problem solved.
Solution: even after correcting the syntax of the query, it didn’t return any results. After making the field BINARY the query started working.

Answer 1

As documented under String Comparison Functions:

Note

Because MySQL uses C escape syntax in strings (for example, “\n” to represent a newline character), you must double any “\” that you use in LIKE strings. For example, to search for “\n”, specify it as “\\n”. To search for “\”, specify it as “\\\\”; this is because the backslashes are stripped once by the parser and again when the pattern match is made, leaving a single backslash to be matched against.

Therefore:

SELECT * FROM `table` WHERE `field` LIKE '%\\\\u0435\\\\u0442\\\\u043e\\\\u0442%'

See it on sqlfiddle.