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Home/ Questions/Q 6218607
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Editorial Team
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Editorial Team
Asked: May 24, 20262026-05-24T07:38:23+00:00 2026-05-24T07:38:23+00:00

I’ve been trying to get a uint64 number into a string, in hex format.

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I’ve been trying to get a uint64 number into a string, in hex format. But it should include zeros. Example:

uint i = 1;
std::ostringstream message;
message << "0x" << std::hex << i << std::dec;
...

This will generate:

0x1

But this is not what I want. I want:

0x0000000000000001

Or however many zeros a uint64 needs.

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  1. Editorial Team
    Editorial Team
    2026-05-24T07:38:24+00:00Added an answer on May 24, 2026 at 7:38 am

    You can use IO manipulators:

    #include <iomanip>
    #include <iostream>
    
    std::cout << std::setw(16) << std::setfill('0') << std::hex << x;
    

    Alternatively, you can change the formatting flags separately on std::cout with std::cout.setf(std::ios::hex) etc., e.g. see here (“Formatting”). Beware that the field width has to be set every time, as it only affects the next output operation and then reverts to its default.

    To get the true number of hex digits in a platform independent way, you could say something like sizeof(T) * CHAR_BIT / 4 + (sizeof(T)*CHAR_BIT % 4 == 0 ? 0 : 1) as the argument for setw.

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