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Home/ Questions/Q 8533543
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Editorial Team
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Editorial Team
Asked: June 11, 20262026-06-11T09:59:04+00:00 2026-06-11T09:59:04+00:00

I’ve been trying to get this working for a bit now… this question has

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I’ve been trying to get this working for a bit now… this question has helped, but I’m still struggling to get this to work. I’d prefer not to install homebrew, because this is a rare task that I’m performing right now.

I have a couple thousand files with a string of text, an underscore, more text, underscore and finally the important file name that I want to preserve. Dropping the first *_*_ and preserving the last part, with file extension, is attempted with \(*\)/\1/.

I’ve tried a couple different things and all I’ve got is the original filenames being spit out again. Any help is appreciated. – not sure if it’s a regex issue, or sed, or probably a little of both.

ls | sed 's/^*_*_\(*\)/\1/' > ouput.txt;
ls | sed 's/^*_*_\(*\$\)/\1/' > out.txt
ls | sed 's/\(^*_*_\)\(*\$\)/\2/' > out.txt
ls | sed 's/\(^.*_+.*_+\)\(.*\$\)/mv & \2/' > out.txt
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  1. Editorial Team
    Editorial Team
    2026-06-11T09:59:05+00:00Added an answer on June 11, 2026 at 9:59 am

    Does this regex do the trick? If not, please report how its output is off (details) and I’ll help you tune it.

    ls -1 | sed -e 's/^[^_]*_[^_]*_//'
    

    Note 1: You may want to use ls -1 to format the files into a single column.

    Note 2: The approach above simply removes the unwanted part of your file names, rather than trying to store in a regex buffer the part that you do want.


    EDIT

    And here’s a bash script that performs the rename.

    for f in `ls -1`
    do
        new_name=`echo "$f" | sed 's/^[^_]*_[^_]*_//'`
        mv "$f" "$new_name"
    done
    

    Can be written as a one-liner, but I went for clarity over brevity.

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